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Two new binary codes with minimum distance three

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1 Author(s)

The author obtains a binary code of length 18 which has 164×26=10496 codewords. The minimum distance of this code is three. Therefore, A(18,3)⩾10496. Shortening, the author obtains find a binary code of length 17 and minimum distance 3 which has 5248 codewords, showing that A(17,3)⩾5248

Published in:

IEEE Transactions on Information Theory  (Volume:34 ,  Issue: 4 )